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2 years ago

Eathan correctly answers 80% of the total questons

Mathematics

1 answer:

KATRIN_1 [288]2 years ago

3 0

Answer:

he got 20% wrong

he got a B

Step-by-step explanation:

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X + 4(x-1) = 9-2(x+3)

Genrish500 [490]

Collect like terms
x + 4x - 4 = 9 - 2 x - 6
move the terms
5x - 4 = 3 - 2x
collect like terms calculate
5x + 2x = 3 + 4
7x = 7
answer is x = 1

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2 years ago

Sanjay has $65 to spend at the mall. He bought a t-shirt for $18. If he want to but a pair of jeans how much can he spend

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answer

$47 because $65 minus $18 is $47

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2 years ago

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If (x + 4) is a factor of f(x), which of the following must be true?

RUDIKE [14]

Answer:

hbvhd6z57dd8ogygfydy

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1 year ago

A climber on Mt Everest is 6000 meters from the start of his trail and at elevation 8000 meters above sea level. At x meters fro

sergeinik [125]

Answer:

h'(x) = 0.6 and Δx = 1 and 2

h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6

h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2

Explanation below:

Step-by-step explanation:

Based on the information given we have that when the climber is 6000 meters from the start, his elevation is 8000 meters above sea level.

We know that the function for elevation is given by h(x) where x is the number of meters from the start.

Therefore, h(6000) = 8000.

We also know that the derivative of a function tells us the reason of change at some point (or how fast a function is changing near that point). For this problem we have that h'(x) = 0.6. (<u>meaning that the elevation increases in 0.6 meters for every meter they hike further nearby the 6000 meters</u>)

We need to use the derivative at a point to estimate values of the function at nearby points

We're going to use h'(x)= 0.6. Δx= 1

h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6

Therefore h (6001) = 8,000.6

Now for h'(x)= 0.6. Δx= 1

h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2

Therefore h(6002) = 8001.2

6 0

2 years ago

Motorola used the normal distribution to determine the probability of defects and the number

vovangra [49]

Answer:

a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4

b.p=0.0026,total defects=2.6

c.Less of the items produced will be classified as defects.

Step-by-step explanation:

a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.

$\mu=10,\sigma=0.15\\Therefore:-\\z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.15}\approx-1.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.15}\approx+1.0\\P(x10.15)=P(Z+1.0)\\=2P(Z$