Which equation is y = (x 3)2 (x 4)2 rewritten in vertex form? y = 2 (x seven-halves) squared minus one-fourth y = 2 (x seven-hal

Question

1 year ago

14

ves) squared minus one-half y = 2(x 7)2 – 73 y = (x 7)2 – 24

1 answer:

Mkey [24] · Answer 1 · 2023-09-17T11:37:44+03:00

The equation when rewritten is $y=2(x-1/2)^2- 27/2$

<h3>Calculations and Parameters:</h3>

When we consider the vertex form of the equation:

y= 3(x-2)^2 - (x-5)^2

Expanding further:

2((x-0.5)^2 - 27/4) = 2( (x-0.5)^2)- 27/2

Thus, the final form of the equation would be $y=2(x-1/2)^2- 27/2$