Question

Which equation is y = (x 3)2 (x 4)2 rewritten in vertex form? y = 2 (x seven-halves) squared minus one-fourth y = 2 (x seven-halves) squared minus one-half y = 2(x 7)2 – 73 y = (x 7)2 – 24

Answer 1

The equation when rewritten is $y=2(x-1/2)^2- 27/2$

Calculations and Parameters:

When we consider the vertex form of the equation:

y= 3(x-2)^2 - (x-5)^2

Expanding further:

2((x-0.5)^2 - 27/4) = 2( (x-0.5)^2)- 27/2

Thus, the final form of the equation would be $y=2(x-1/2)^2- 27/2$

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