1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yan [13]
3 years ago
10

What is the surface area of the​ solid?

Mathematics
2 answers:
sertanlavr [38]3 years ago
5 0

Answer:

othe large one is 234 i ran out of time sorry i didnt get  circleto t

Step-by-step explanation:

dem82 [27]3 years ago
5 0

Answer:

347.04 m²

Step-by-step explanation:

Total surface area = central rectangular prism + (1/2 left + 1/2 right)cylinder

a = 2x(11x3+11x6+6x3) + (2xπx(6/2)²+2xπx(6/2)x3)

  = 234 + 113.04

  = 347.04

You might be interested in
String a is 35 centimeters long. String B is 5 times as long as string A. Both are necessary to create a decorative bottle. Find
ss7ja [257]

Answer:

Total length of string required for 17 decorative bottles = 35.7\ m

Step-by-step explanation:

Length of string A = 35\ cm =\frac{35}{100} =0.35\ m

Length of string B = 5\times A = 35\times 5 =175\ cm = \frac{175}{100} = 1.75\ m

Total length of the string required for decorating one bottle = Summation of string A and String B,used =1.75+0.35 = 2.10\ m

To find the string needed for 17 bottles we will multiply the strings used for 1 bottle with 17.

So 2.10\times 17 =35.7\ m.

The total length of string needed for [tex}17{/tex} bottles is =35.7\ m.

8 0
4 years ago
2^x-1=128<br><br><br> show work pls! thank u :)
hichkok12 [17]

Hello from MrBillDoesMath!

Answer:

Take you pick below!   (either x 8 or x = 7.01, approx, depending how the question is interpreted)




Discussion:

Interpretation 1

If the question is   2^(x -1)  = 128, then as 2^7 = 128,

x-1 = 7 so x = 8



Interpretation 2

If the question is (2^x -1) = 128, then..

2^x  = 128 + 1 = 129  =>

log(2^x) = log(129) =>

xlog(2) = log(129) =>

x = log (129) / log2 = 7.01

Regards,  

MrB

4 0
3 years ago
Devon purchased one bag of dog food and three bags of cat food. Each bag of dog food weighs x pounds and each bag of cat food we
likoan [24]

Answer:

A pound of cat food will weigh 6.5 pounds

Step-by-step explanation:

Firstly, we need to get the value of x. Thus, let’s solve the equation at hand;

x + 3x/2 = 32.5

x + 1.5x = 32.5

2.5x = 32.5

x = 32.5/2.5

x = 13

Now from the question, we are made to know that a pound of cat food measures half of what a pound of dog food measures

Since we calculate a pound of dog food to weigh 13 pounds, a pound of cat food will weigh = 13/2 = 6.5 pounds

6 0
4 years ago
Lauren says that two expressions 3x+4(2x+5) and 6x +5x . do these equal the same
spin [16.1K]

<em>these do not equal the same. </em>

step by step: 3x + 4 (2x + 5)

multiply 4 by 2x, which is 8, then multiply 4 by 5, which is 20.

simplify; 3x + 8x + 20

combine like terms; (3x + 8x) + (20)

you’ll come up with 11x + 20

step by step: 6x + 5x

just add the two together and... bam, you get 11x.

4 0
4 years ago
Find the cost per visit to the nearest cent: Health and Heart Club, $259 per year, 3 visits per week.
spin [16.1K]

Answer:

$259/3=86.333333333333333333333333333333333333333333333333333

Step-by-step explanation:


6 0
4 years ago
Read 2 more answers
Other questions:
  • What is 7(2b+5) rewrtitten using the Distributive Property?
    12·2 answers
  • PLZ HELP!
    15·2 answers
  • 4. Charlie drove from Calgary to Saskatoon, which is a distance
    7·1 answer
  • Find the midpoint of the line segment.
    10·2 answers
  • The average of Cindy’s three test scores must be greater than 76 for her to pass the class
    9·1 answer
  • Help plz!!!!!!!!.!.!.!.!.!.!.!.!.!!
    10·2 answers
  • Determine the product (4.2×10^-1)+(5.7+10^-1)​
    11·1 answer
  • 36 divided by the quantity 5 plus p​
    12·1 answer
  • Pls hurry will give brainliesttt
    14·1 answer
  • What value must be filled in the blank in order to complete the square?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!