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1 year ago

The osmoregulatory and ionoregulatory problems facing a freshwater fish are:.

Biology

1 answer:

Leona [35]1 year ago

6 0

Answer:

The hallenges are;

a. Osmoregulatory challenges

i. Water influx

b. Ionoregulatory challenges

i. Salt loss2.

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Shana is a competitive athlete who weighs 135 lb. she would like to plan a nutritionally adequate diet that provides enough carb

sashaice [31]

Carbohydrates are your body’s main source of energy. The amount of carbs a man should consume daily depends on his age and activity level. The Institute of Medicine suggests adults to eat at least 130 grams of carbs a day. But If you’re a competitive athlete like Shana, you need additional amount.

<span>A study made by The Academy of Nutrition and Dietetics recommends a 2.3 to 4.5 grams of carbohydrates per pound of body weight each day, to athletes depending on the intensity of training. Therefore, Shana who weighs 135 lbs, needs approximately 310.5 grams carbohydrates daily for her physical workouts. </span>

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2 years ago

4. What is the difference between biosphere and ecosystem?

aalyn [17]

The biosphere is everything that makes up life like plants and animals for instance but ecosystem is all the living and nonliving factors that affect the area hope this helps

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3 years ago

Read 2 more answers

Which of the following statements is correct in regards to the deep ocean circulation of water in the ocean?

Hoochie [10]

Answer:

the answer is C

Explanation: The deep ocean circulation of water is caused by convection currents in water that allow cold water to rise and warm water to sink.

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3 years ago

100 points + brainliest:3

trasher [3.6K]

Answer:

1. C

2. B

3. A

4. C

5. D

6. A

7 0

2 years ago

An individual heterozygous for eye color, skin color, and number of eyes mates with an individual who is homozygous recessive fo

sukhopar [10]

Answer:

B) 1 black eyes, green skin, two eyes : 1 black eyes, green skin, one eye : 1 black eyes, white skin, two eyes : 1 orange eyes, green skin, two eyes : 1 orange eyes, white skin, two eyes : 1 orange eyes, white skin, one eye

Explanation:

Parentals: BbGgCc x bbggcc

The punette square diagram of the cross of these two parents is attached.

B = black eyes, b = orange eyes;

G = green skin, g = white skin;

C = two eyes, c = one eye

Progeny with BbGgCc genotype → black eyes, green skin, two eyes = 8

Progeny with BbGgcc genotype → black eyes, green skin, one eye = 8

Progeny with BbggCc genotype → black eyes, white skin, two eyes = 8

Progeny with bbGgCc genotype → orange eyes, green skin, two eyes = 8

Progeny with Bbggcc genotype → black eyes, white skin, one eye = 8

Progeny with bbGgcc genotype → orange eyes, green skin, one eye = 8

Progeny with bbggCc genotype → orange eyes, white skin, two eyes = 8

Progeny with bbggcc genotype → orange eyes, white skin, one eye = 8

So, if we will see them in the form of ratio then each of the genotype will be in the ratio of 1 i.e. black eyes, green skin, two eyes: black eyes, green skin, one eye: black eyes, white skin, two eyes: orange eyes, green skin, two eyes: black eyes, white skin, one eye: orange eyes, green skin, one eye: orange eyes, white skin, two eyes : orange eyes, white skin, one eye = 1:1:1:1:1:1:1:1.

So, in view of above option B is most appropriate.

Note: In a trihybrid cross, a total of 64 progeny types may be produced.

6 0

2 years ago