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BARSIC [14]
1 year ago
14

Pls help!! need ur help math geniuses help with my last question! ty

Mathematics
1 answer:
Shtirlitz [24]1 year ago
7 0

The expected value of the discrete distribution is of 20.97, hence option C gives the correct answer.

<h3>What is the mean of a discrete distribution?</h3>

The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability.</u>

Hence, according to the table, the expected value is given by:

E(X) = 12 x 0.08 + 18 x 0.15 + 20 x 0.31 + 22 x 0.08 + 24 x 0.15 + 25 x 0.23 = 20.97.

More can be learned about the expected value of a discrete distribution at brainly.com/question/26660401

#SPJ1

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Step-by-step explanation:

8a-6+a-1

Collect like terms

8a+a-6-1

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2 years ago
The profit P (in thousands of dollars) for an educational publisher can be modeled by P 52b31 5b21b where b is the number of wor
Anna007 [38]

Answer:

The lesser number of workbooks are 1,000

Step-by-step explanation:

The correct question is

The profit P (in thousands of dollars) for an educational publisher can be modeled by P=-b³+5b²+b where b is the number of workbooks printed (in thousands). Currently, the publisher prints 5000 workbooks and makes a profit of $5000. What lesser number of workbooks could the publisher print and still yield the same profit?

we have

P=-b^3+5b^2+b  

For P=\$5,000

substitute in the equation and solve for b

Remember that the profit and the number of workbooks is in thousands

so

P=5

5=-b^3+5b^2+b

Using a graphing tool

Solve the cubic function

The solutions are

x=-1

x=1

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therefore

The lesser number of workbooks are 1,000

<u><em>Verify</em></u>

For b=1

P=-(1)^3+5(1)^2+1  

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so

P=\$5,000 ----> is ok

7 0
3 years ago
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