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Nuetrik [128]
3 years ago
12

What is the midpoint of BC

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
5 0

Answer:

(5, 6 )

Step-by-step explanation:

Using the midpoint formula

[ 0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

with (x₁, y₁ ) = B(2, 1) and (x₂, y₂ ) = C(8, 11)

midpoint = [ 0.5(2 + 8), 0.5(1 + 11) ] = (5, 6 )

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