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2 years ago

Which equation best fits the graph below?

Mathematics

1 answer:

stepladder [879]2 years ago

8 0

The answer is y = 1/2x + 2

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Descent, Inc., produces a variety of climbing and mountaineering equipment. One of its products is a traditional three-strand cl

Rainbow [258]

Solution :

Assuming $\sigma_1^2=\sigma_2^2$

We have to test

$H_0:\mu_1=\mu_2$

Against $H_a: \mu_1 \neq \mu_2$

Level of significance, $\alpha = 0.05$

$s_p=\sqrt{\frac{(n_1-1)s_1^2+ (n_2-1)s_2^2}{n_1+n_2-2}}$

$s_p=\sqrt{\frac{(25-1)(425)^2+ (20-1)(415)^2}{25+20-2}}$

= 420.6107

Under $H_0$ , the t-statistics is as follows:

$t=\frac{(\overline{x_1} - \overline{x_2})}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}} \sim$ $\text{t with }(n_1+n_2-2) \ DF$

$t=\frac{(7200-7087)}{(420.6107)\sqrt{\frac{1}{25}+\frac{1}{20}}}$

= 0.90

DF = (25 + 20 - 2)

= 43

P-value of the test = 0.375

Since the p value is more than 0.05, we fail to reject our null hypothesis.

There is no difference between then mean tensile strength of the ropes that is produced in the Bozeman and Challis.

3 0

3 years ago

055

Citrus2011 [14]

B. 855/4.5 is 190. Out of all four choices, 475 cal / 2.5 servings is the only which leave you 190.

4 0

3 years ago

A study of the career paths of hotel general managers sent questionnaires to an SRS of 160 hotels belonging to major U.S. hotel

otez555 [7]

Answer:

(10.78483, 12.61517)

Step-by-step explanation:

It is given that the genera mangers of few hotels were sent some questionnaires for conducting a study for the career paths in the major hotel chains of the United States.

Number of hotels = 160

Number of response received = 103

The average number of years these general mangers was in their current hotels, $\bar x$ = 11.7 years

Confidence Interval, CI = 0.99

Therefore,

a = 0.01, |Z(0.005)| (from standard normal table)

∴ 99% of CI = $\bar x \pm Z \times \frac{s}{\sqrt n}$

$= 11.7 \pm 2.58 \times \frac{3.6}{\sqrt {103}}$

$(10.78483, 12.61517)$

3 0

3 years ago

What is 925 divided by 264

Leni [432]

Answer:

3.50378787879

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A sample of 100 independent random numbers is taken from this distribution, and its average is used to estimate the mean of the

Mariulka [41]

Answer:

The standard error in estimating the mean = (0.1 × standard deviation of the distribution)

Step-by-step explanation:

The standard error of the mean, for a sample, σₓ is related to the standard deviation, σ, through the relation

σₓ = σ/(√n)

n = sample size = 100

σₓ = σ/(√100)

σₓ = (σ/10) = 0.1σ

Hence, the standard error in estimating the mean = (0.1 × standard deviation of the distribution)

4 0

3 years ago