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2 years ago

Help me on number.4 please

Mathematics

1 answer:

Artemon [7]2 years ago

8 0

I can do it using trigonometry.

Draw a line from O to the point where the circle touches the base line. This will be at right angles to EF and will have length 40. Then draw a line from A parallel to the base to meet OG at H.

consider triangle OAH:-

side OH = 40-25 = 15 cm

cos < AOH = 15/40 giving m < AOH = 67.976 degrees

So m < AOB = 67.976 * 2 = 135.95 degrees

in radians this is 2.37 radians (answer)

Part B:-

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If 2000 dollars is invested in a bank account at an interest rate of 6 percent per year, find the amount in the bank after 7 yea

AfilCa [17]

Answer:

$3007.26

Step-by-step explanation:

Step one:

given data

Principal= $2000

rate= 6%= 0.06

time= 7years

Required:

The final amount A

Step two:

the expression for the compound interest is

$A= P(1+r)^t$

substituting we have

$A= 2000(1+0.06)^7\\\\A= 2000(1.06)^7\\\\A=2000*1.50363\\\\A=3007.26$

6 0

2 years ago

The number of minutes Magdeline spent talking on her cell phone each month for the past five months were 494, 690, 502, 478, and

snow_lady [41]

Answer:

542 minutes

Step-by-step explanation:

currently our mean is =530

i got that by adding all the number out which equal too =2,650

and divide it by how many number there are which is 5

2,650/5=530

After some trial and error i found it

so you add 494+690+502+478+486+542=3,192

3,192/6=532

and that was our goal

so the 6th month she talked on the phone for 542 minutes

pls mark me brainliest

7 0

3 years ago

Unit 3, Lesson 7

aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

Given:

A car travels 55 miles per hour for 2 hours.

So the speed of the car 55 miles per hour is constant for 2 hours.

Using speed formula.

$Speed=\frac{distance}{time}$

Second row.

From the second row of the table $time = \frac{1}{2}=0.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{0.5}$

$distance = 55\times 0.5$

$distance = 27.5\ mi$

Third row.

From the third row of the table $time =1\frac{1}{2}=\frac{3}{2} = 1.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{1.5}$

$distance = 55\times 1.5$

$distance = 82.5\ mi$

Fourth row.

From the fourth row of the table $distance =110\ miles$ and speed is constant $speed = 55\ mi/hr$ , so we need to find time.

$Speed=\frac{distance}{time}$

$time=\frac{distance}{speed}$

$time=\frac{110}{55}$

$time = 2\ sec$

Therefore we complete the table from the above calculation.

8 0

3 years ago

The product 3/4 times 1/2 will be less than or greater than 3/4

Komok [63]

Answer:

less

Step-by-step explanation:

first you would multiply and get 4/8, which simplifies to 1/2, which would be 2/4, which is less than 3/4

3 0

2 years ago

Read 2 more answers

If DF = 9x-39, find EF.

otez555 [7]

$DF=DE+EF\\\\DF=9x-39\\DE=47\\EF=3x+10\\\\\text{substitute}\\\\9x-39=47+3x+10\\9x-39=3x+57\ \ \ |-3x\\6x-39=57\ \ \ \ |+39\\6x=96\ \ \ \ |:6\\x=16\\\\\text{put the value of x to the expression}\ 3x+10\\\\EF=3(16)+10=48+10=58$

Answer: EF = 58

7 0

2 years ago