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Vinil7 [7]
2 years ago
12

Genevieve brought $35.75 to the art supply store. She bought a brush, a sketchbook, and a paint set. The brush was 1/6 as much a

s the sketchbook, and the sketchbook cost 3/4 the cost of the paint set. Genevieve had $2.00 left over after buying these items.
Mathematics
1 answer:
leonid [27]2 years ago
6 0

The cost of a brush, a sketchbook, and a paint set will be $ 2.38, $ 14.3, and $ 19.067 respectively.

<h3>What is the linear system?</h3>

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Genevieve brought $35.75 to the art supply store.

She bought a brush, a sketchbook, and a paint set.

Let x be the cost of the paint set.

The sketchbook cost 3/4 the cost of the paint set. Then the cost of the sketchbook will be

\rightarrow \rm \dfrac{3x}{4}

The brush was 1/6 as much as the sketchbook. Then the cost of the brush will be

\rightarrow \rm \dfrac{3x}{4} \times \dfrac{1}{6}=\dfrac{x}{8}

Then the value of the paint set will be

\begin{aligned} \dfrac{3x}{4} +\dfrac{x}{8} + x &= 35.75\\\\\dfrac{15}{8}x &= 35.75\\\\15x &= 286\\\\x &= \$ 19.067 \end{aligned}

Then the cost of the sketchbook will be

→ 3 × 19.067 / 4 = $ 14.3

Then the cost of the brush will be

→ $ 2.38

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ1

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Estimate the perimeter of the figure to the nearest tenth.
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<em>The Perimeter of the Figure to the nearest tenth is 18.7 units</em>

Step-by-step explanation:

<em>Please note I have attached an edited version of your sketch to aid my solution. Now this question can be solved in multiple ways. Here, we shall see one of them. </em>

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Looking at the original sketch, we can see that the figure is actually a combination of a Triangle (Figure 1 in my sketch) and a rectangle (Figure 2 in my sketch). So we can simply find the sides of a Triangle and the sides of a Rectangle and add them.

<u>Perimeter on Figure 1:</u>

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<u>Perimeter on Sketched Figure:</u>

<u><em>The perimeter of the total figure will be two sides of the triangle and the three sides of the rectangle (as the one adjacent between Fig. 1 and 2 can not be taken into account). Thus we need to find 5 different sides and add them together. </em></u>

Now since the figure is on a <em>graph paper</em>, we can read of the size of some sides, thus the left side of the triangle is a=3 units and the base of the triangle is also b=3 units. Now to find the last unknown side we can take Pythagorian theorem, since our triangle is a Right triangle, (i.e. one angle is 90°).

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h^2=a^2+b^2\\

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h=\sqrt{a^2+b^2}\\ h=\sqrt{3^2+3^2}\\\\h=\sqrt{9+9}\\ h=\sqrt{18}\\ h=3\sqrt{2} units.

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