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PtichkaEL [24]
2 years ago
7

Simplify −4+x≤9 PLEASEE

Mathematics
2 answers:
Alenkinab [10]2 years ago
8 0

                - - - - - - - - - - - - - - - - - - - - - - - - -

\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond

             Simplify -4+x≤9.

\diamond\large\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}\diamond

      ❖ Add 4 on both sides:-

x≤9+4

x≤13

  ✯ So the values of x less than or equal to 13 will make this inequality true.

<h3>Good luck.</h3>

        - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Gennadij [26K]2 years ago
3 0

Answer: HEYAA :))

I THINK YOUR ANSWER IS x≤13

Step-by-step explanation:

Solve for x by simplifying both sides of the inequality, then isolating the variable.

HOPEFULLY THIS HELPS YOOUUU

- MATTHEW ~^^

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Ludmilka [50]

Answer:

Step-by-step explanation:

-4 (-2x - 8) = -48

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3 0
3 years ago
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Find the points of intersection between x^2+y^2=45 and -3x+y=15​
MatroZZZ [7]

Step-by-step answer:

Given:

Circle C1: x^2+y^2 = 45

Line L1: -3x+y=15

Need to find the points of intersection.

Solution:

basically we need to solve for the roots of equations C1 and L1.

Here, we can use substitution of L1 into C1.

Rewrite L1 as : y=3x+15

substitute into C1:

x^2+(3x+15)^2 = 45

Expand

x^2 + 9x^2+90x+225 = 45

Rearrange terms:

10x^2+90x+180 = 0

Simplify

x^2+9x+18 = 0

Factor

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Back-substitute x into L1 to calculate y:

x=-6, y=3*x+15 = 3(-6)+15 = -3  => (-6,-3)

x=-3, y=3*x+15 = 3(-3) + 15 = 6 => (-3, 6)

Therefore the intersection points are (-6,-3) and (-3,6)

Check using equation C1:

(-6)^2+(-3)^2 = 36+9 = 45  ok

(-3)^2+(6)^2 = 9 + 36 = 45 ok

Check using equation L1:

Point (-6,-3) : y = 3x+15 = 3(-6) +15 = -3  ok

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4 years ago
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
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I need help please ..
swat32

The answer to this is 4 as J is equivalent as 4 because if you substitute each letter with its value you will end up with an amount of 4

So H is 4

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