Solve the system of inequalities. (Note: you may need to adjust your scale on the coordinate plane.) Show work

Mathematics

1 answer:

Mars2501 [29]2 years ago

8 0

Answer:

Step-by-step explanation:

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frosja888 [35]

Answer:

Step-by-step explanation:

B, because -9.2 = -4.5, which is less than -4.12. Also, 17/4 = 4.25 is less than sqrt(20), which is 4.4721

6 0

2 years ago

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Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$

Since

$\int\limits^1_0 {x^{2} } \, dx = 13$ ,

Substituting this into the equation the equation, we have

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Learn more about definite integrals here:

brainly.com/question/17074932

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2 years ago

Equivalent answers for 64 to the power of 2/3

madreJ [45]

Answer:

Step-by-step explanation:

Dealing with a fraction exponent on hand can be converted by using the fractional exponents rule where the fraction exponent is converted to something like this:

$64^\frac{2}{3} = \sqrt[3]{64^{2}}\\$