A particular gene has two alleles, a dominant allele A and a recessive allele a. The frequency of allele A is 0.55. If the popul
ation is in Hardy-Weinberg equilibrium with respect to the gene, then what is the expected frequency of genotype Aa
1 answer:
If p = frequency of A and q = frequency of a, then assuming H-W equilibrium we have
p + q = 1 ⇒ q = 1 - p = 1 - 0.55 = 0.45
Then the expected frequency of the heterozygous genotype Aa is 2pq = 2 • 0.55 • 0.45 = 0.495.
You might be interested in
It's B. 10 to 20 percent.
Answer:
Ignore this
Explanation:
Answer:
A.) They are different species, despite their similar morphology.
Explanation: