The line equation in slope-intercept form is y=mx+b
You have one line with a y-intercept at 1 and a slope of -3 -> y=-3x+1
and another with a y-intercept at -1 and a slope of
-> ![y=\frac{1}{2}x-1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B2%7Dx-1)
The area marked is below the first line and above the second one -> replace = with < and >:
y<-3x+1
![y>\frac{1}{2}x-1](https://tex.z-dn.net/?f=y%3E%5Cfrac%7B1%7D%7B2%7Dx-1)
Which is the system of linear inequalities shown in the graph
Answer:
Step-by-step explanation:
660
110 6
55 2 <em> 3</em> <em>2</em>
<em>11</em><em> </em> <em>5 </em>
The answer is 2^2x3x5x11
Since 15409-1=15408 and 15408+1=15409, we can write that as one. With 15409-2, we can write the same thing with 15407+2
Answer:
4 is the answer to your question
Step-by-step explanation:
Answer:
x=10
Step-by-step explanation:
By the Trapezoid Midsegment Theorem, the midsegment of a Trapezoid is 1/2(the sum of the 2 bases.
4x-20=1/2(23+17)
4x-20=1/2(40)
4x-20=20
4x=40
x=10