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3 years ago

HelpppI don't know it's correct

Mathematics

2 answers:

Hunter-Best [27]3 years ago

6 0

Answer:

yes its correct

Whole numbers are located at the right side of the number line .

0 is the smallest whole number

negative numbers are not whole numbers

Hope that helped

Step-by-step explanation:

bezimeni [28]3 years ago

4 0

Answer:

Yes it is correct

Step-by-step explanation:

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Find the slope of a line that is parallel and the slope of a line that is perpendicular to each line whose equation is given. Pl

aleksley [76]

The equations above are all in the format $y = mx + c$ , where $m$ = the gradient, or slope.

So, in the first question, $y = 4x + 2$ , the gradient would be 4, because 4 is $m$ in this equation (the number before the $x$ ).

The gradient of a line perpendicular to this line is equal to the negative reciprocal of the gradient of the line. A better way to explain it is if $m$ = the gradient of the line and <u /> $m'$ = the gradient of the perpendicular line then:
$m' = - \frac{1}{m}$

So in the first question, the gradient of the perpendicular line is $- \frac{1}{4}$ .

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3 years ago

Find cos θ if csc θ = 2 and θ is in quadrant II.

natita [175]

Cosecant is one of the six trigonometric identities which is equal to the reciprocal of sine function. In this case, theta is equal to sin -1 = 1/2 equal to 30 degrees. Since this is in quadrant II, the angle is 180 - 30 or 150 degrees. cos 150 is equal to -0.866 or -ssqrt 3 over 2.

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3 years ago

Find the volume of each pyramid or come. Round to the nearest tenth if necessary.

Naya [18.7K]

QUESTION 1

The given pyramid has a square base.

The volume of this square pyramid is given by;

$V=\frac{1}{3}\times l^2\times h$

where $l=5ft$ is the length of a side of the square base.

and $h=8ft$ is the height of the pyramid.

We substitute the values into the formula to get;

$V=\frac{1}{3}\times 5^2\times 8 ft^3$

$V=66.7 ft^3$

QUESTION 2

The given pyramid has a rectangular base.

The volume of this rectangular pyramid is given by;

$V=\frac{1}{3}\times l\times b\times h$

where $l=7cm$ and w=4cm are the length and width of a side of the rectangular base.

and $h=8cm$ is the height of the pyramid.

We substitute the values into the formula to get;

$V=\frac{1}{3}\times 7\times 4\times 8cm^3$

QUESTION 3

The given pyramid has a rectangular base.

The volume of this rectangular pyramid is given by;

$V=\frac{1}{3}\times l\times b\times h$

where $l=10in.$ and w=8in are the length and width of a side of the rectangular base respectively.

There is a right triangle created inside this pyramid that can help us find the height of this pyramid.

Notice that the base of this right triangle is half the width of the rectangular base (4in.) and the hypotenuse is 14in.

We need to use Pythagoras Theorem to find the height of this pyramid.

$h^2+4^2=14^2$

$h^2+16=196$

$h^2=196-16$

$h^2=180$

$h=\sqrt{180}$

$h=6\sqrt{5}in.$

We substitute the values into the formula to get;

$V=\frac{1}{3}\times 10\times 8\times6\sqrt{5}in^3$

$V=160\sqrt{5}in^3$

$V=357.8in^3$

QUESTION 4

The radius of the base of the given cone is 12m.

The height of the cone is 25m.

The volume of a cone is calculated using the formula;

$V=\frac{1}{3}\pi r^2h$

We substitute the given values to get;

$V=\frac{1}{3}\pi 12^2\times 25m^3$

$V=3769.9m^3$

QUESTION 5

The given cone has diameter 14yd.

The radius is half the diameter, r=7yd

The radius(7yd), the height (h), and the slant height(25yd being the hypotenuse) form a right triangle.

We apply the Pythagoras Theorem again to get;

$h^2+7^2=25^2$

$h^2+49=625$

$h^2=625-49$

$h^2=576$

$h=\sqrt{576}$

$h=24$

The height of the cone is 24yd.

The volume of a cone is calculated using the formula;

$V=\frac{1}{3}\pi r^2h$

We substitute the given values to get;

$V=\frac{1}{3}\pi 7^2\times 24yd^3$

$V=1231.5yd^3$

QUESTION 6

The height of the given cone is 18mm.

The radius can be calculated using the tangent ratio.

$\tan(66\degree)=\frac{18}{r}$

$r=\frac{18}{\tan(66\degree)}$

$r=8.0141yd$

The volume of a cone is calculated using the formula;

$V=\frac{1}{3}\pi r^2h$

We substitute the given values to obtain;

$V=\frac{1}{3}\pi 8.0141^2\times 18mm^3$

$V=151.1mm^3$

7 0

3 years ago

11.1 divide by 0.01 is equal to ?

Mumz [18]

The answer is 1110

step by step explanation:

4 0

3 years ago

Read 2 more answers

Please answer #’s 6-10

mr_godi [17]

Answer:

6-10 equals -3

Step-by-step explanation:

4 0

3 years ago

HelpppI don't know it's correct​

HelpppI don't know it's correct