Is an equation considered an identity if there is already a solution for the variable? For example I solved 6z+24=3z and got z=-
1 answer:
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Answer:
$1,061.76
Step-by-step explanation:
(refer to attached handout)
For compound interest, you are given:
A = ? (need to find)
P = $1000
r = 3% = 0.03
n = compounded monthly = 12 times per year
t = 2 years
(substituting this into the formula)
A = P [ 1 + (r/n) ] ^(nt)
A = 1000 [ 1 + (0.03/12) ] ^[(12)(2)]
A = 1000 [ 1 + 0.0025 ] ^24
A = 1000 [ 1.0025 ] ^24
A = 1,061.76
