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noname [10]
3 years ago
9

Please help! Brainliest

Mathematics
1 answer:
vladimir1956 [14]3 years ago
6 0
C) 84
7(6x2)


Sry if it’s wrong
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Examples of terminating
steposvetlana [31]

Answer:Terminating decimals: Terminating decimals are those numbers which come to an end after few repetitions after decimal point. Example: 0.5, 2.456, 123.456, etc. are all examples of terminating decimals.

Step-by-step explanation:

:D

5 0
3 years ago
Cual es la respueta para 2/67 multiplicado por 34/67
ivolga24 [154]
<span>La respuesta es 68/4489 en términos más bajos.</span>
3 0
3 years ago
Find the major axis for the ellipse <br> x² + 16y2-96y + 128 = 0
Softa [21]

The major axis for the ellipse, x² + 16y² - 96y + 128 = 0 is the x-axis

To answer the question, we need to write it in the standard form of the equation of an ellipse

<h3>Equation of an ellipse</h3>

The equation of an ellipse centered at  (h,k) is

(x - h)²/a² + (y - k)²/b² (1) where a > b and the major axis is parallel to the x axis

Given x² + 16y² - 96y + 128 = 0, we convert it into the standard equation of an ellipse.

So, x² + 16y² - 96y + 128 = 0

Dividing through by 16, we have

x²/16 + 16y²/16  - 96y/16 + 128/16 = 0/16

x²/16 + y² - 6y + 8 = 0

Completing the square in y by adding and subtracting (-6/2)² = (-3)²

x²/16 + y² - 6y + (-3)² - (-3)² + 8 = 0

x²/16 + (y - 3)² - 9 + 8 = 0

x²/16 + (y - 3)² - 1 = 0

x²/16 + (y - 3)² = 1

x²/4² + (y - 3)²/1² = 1  (2)

Comparing equations (1) and (2), we have that a = 4 and b = 1.

Since a = 4 > b = 1, the major axis for the ellipse is the x-axis

So, the major axis for the ellipse, x² + 16y² - 96y + 128 = 0 is the x-axis

Learn more about ellipse here:

brainly.com/question/26679189

#SPJ1

8 0
2 years ago
Jose asks his friends to guess the higher of two grades he received on his math tests. He gives them two hints. The difference o
AlekseyPX

Answer : 96

x – y = 16 --------> equation 1

\frac{1}{8} x +\frac{1}{2} y = 52

x is the higher grade and y is the lower grade

We solve the first equation for y

x - y = 16

-y = 16 -x ( divide each term by -1)

y = -16 + x

Now substitute y in second equation

\frac{1}{8} x +\frac{1}{2} ( -16 + x ) = 52

\frac{1}{8} x - 8 +   \frac{1}{2} x = 52

\frac{1}{8} x  +   \frac{1}{2} x - 8 = 52

Take common denominator to combine fractions

\frac{1}{8} x  +   \frac{4}{8} x  -8 = 52

\frac{5}{8} x - 8  = 52

Add 8 on both sides

\frac{5}{8} x   = 60

Multiply both sides by \frac{8}{5}

x = 96

We know x is the higher grade

96 is the higher grade of Jose’s two tests.

6 0
3 years ago
Read 2 more answers
What is the y-intercept of y= -.25 + 2?
sp2606 [1]

Answer:

2 (if the -.25 has an x after it)

If not 1.75

4 0
3 years ago
Read 2 more answers
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