<span>_____Balanced Chemical eqn___
C6H5OH + 7O2 --> 6C02 + 3H20
Firstly, heat of rxn will be absorbed by bobm calorimaeter, so find the qcal
qcal = CΔT
= (11.66 KJ/°C)(26.37°C- 21.36°C)
= 58.42 KJ
since the heat of rxn absorbed by calorimeter, assume:
qrnx = -qcal
= - 58.42 KJ
_____q GRAM OF C6H5OH______
Find the number of moles you have by dividing the given grams of C6H5OH by its molar mass
(1.8 g C6H5OH)(94 g/mole C6H5OH) = 0.0191 mol C6H5OH
then divide qrnx by the number of moles.
(-58.42 KJ)/(0.0191 mol C6H5OH) = -3058.64 KJ/mol C6H50H</span>
That’s picture right there should help u with your works
Answer:
mass of ice is 1.75
Explanation:
Using, the formula given in the question,
m = Q/HΔf.................. Equation 1
Where Q = Heat, m = mass of ice, HΔf = Latent heat of fussion of for ice.
From the question,
Given: Q = 584.5 J, HΔf = 334 J/g
Substitute these values into equation 2
m = 584.5/334
m = 1.75 kg.
Hence the mass of ice without unit is 1.75
Answer:
There are 0.1 moles of solute in 250 mL of 0.4 M solution
Explanation:
because it is
Answer:
If a metal and metal solution react, the more reactive metal will displace the less reactive metal from solution. If the metal in solution you start with is formed from a more reactive metal than the metal to be added, no reaction will occur.
