Answer:
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Answer: The following code is in c++
#include <iostream>
#include<math.h>
using namespace std;
int main()
{
float a,b,c;
cout<<"Enter height and base of triangle\n";
cin>>a>>b; //reading two sides from user
c=sqrt(pow(a,2)+pow(b,2)); //calculating hypotenuse
cout<<"Length of hypotenuse is "<<c; //printing third side of triangle
return 0;
}
OUTPUT :
Enter height and base of triangle
3
4
Length of hypotenuse is 5
Explanation:
In the above code, three variables a, b and c of int type are declared. After that, it is asked from user to enter the value of a and b. The user puts the value and then c is calculated with the help of Pythagoras theorem formulae which squares the values of two sides and then adds them to calculate hypotenuse of a right angled triangle and finally c is printed to console.
L is a decidable language because the Turing machine accepts it.
L is a recognizable language if TM M recognizes it.
<h3>How do you know if a language is decidable?</h3>
A language is said to be decidable only when there seems to exists a Turing machine that is said to accepts it,
Here, it tends to halts on all inputs, and then it answers "Yes" on words that is seen in the language and says "No" on words that are not found in the language. The same scenario applies to recognizable language.
So, L is a decidable language because the Turing machine accepts it.
L is a recognizable language if TM M recognizes it.
Learn more about programming language from
brainly.com/question/16936315
#SPJ1
Font(s)
fonts is another word for typeface
the appearance of letters and numbers when you chang the font
