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2 years ago

The value of the x-intercept for the graph of 4x-5y=40 is

Mathematics

1 answer:

Alik [6]2 years ago

8 0

$\hbox{x-intercept - y=0}: \\
4x-5 \times 0=40 \\
4x=40 \\
x=\frac{40}{4} \\
\boxed{x=10}$

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7) If £1 = €1.14. Work out what €144 is in pounds.

jonny [76]

Answer:

$126\frac{6}{19}$ £

Step-by-step explanation:

£1 = €1.14 / $*\frac{144}{1.14}$

£ $\frac{144}{1.14}$ =144€= $126\frac{6}{19} \\$ £

8 0

3 years ago

Expand (2x+2)^6 How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

8 0

1 year ago

Solve the separable differential equation dtdx=x2+164 and find the particular solution satisfying the initial condition x(0)=9

maria [59]

$\dfrac{dt}{dx} = x^2 + \frac{1}{64} \Rightarrow\ dt = \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ \\ \displaystyle \int 1 dt = \int \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ t = \dfrac{x^3}{3} + \frac{x}{64} + C$

C = 9 because all the x terms go away.

$t = \dfrac{x^3}{3} + \dfrac{x}{64} + 9$

3 0

3 years ago

What is the domain of F(x)=√x ? (PLEASE HELP ASAP)

leva [86]

Option C. all real numbers greater than 0 is the correct answer

Further explanation:

Domain is the set of all inputs on which the function is defined or real.

The given function is:

$f(x)=\sqrt{x}$

As the function involves a square root, we have to avoid negative numbers.

All positive real numbers will produce defined output so the positive real numbers will be included in the domain.
If we look at negative real numbers, we will be taking square root of a negative number which will not result in a real number

So the domain will only include positive real numbers.

Hence, Option C. all real numbers greater than 0 is the correct answer.

Keywords: Domain, Domain of radical functions

Learn more about domain at:

#LearnwithBrainly

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3 years ago

Katy invests a total of $13,000 in two accounts paying 2% and 7% annual interest, respectively. How much was invested in each ac

kherson [118]

Answer:

2 % amount = 12000 7% amount = 1000 dollars

Step-by-step explanation:

x = 2% amount

then 13 000 - x = 7% amount

.02x + .07 (13000-x) = 310

-.05x + 910 = 310

.05x = 600

x = 600/.05 = 12000 then the 7% amount is 1000

4 0

1 year ago