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1 year ago

Can someone teach me how to answer this? Thanks!

Mathematics

1 answer:

DaniilM [7]1 year ago

5 0

Answer:

$\left( fg\right) \left( x\right) =2x^3\sqrt[3]{x}\\\\\left( \frac{f}{g} \right) \left( x\right) =\frac{2x^{3}}{\sqrt[3]{x} }$

Step-by-step explanation:

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2 years ago

J. Reexamine the sequence 20, 14, 8, 2, ... from the problem

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Answer:

The n th of the given sequence is $t_{n} = 26-6 n$

Step-by-step explanation:

<u>Step 1</u> :-

Given sequence is 20,14,8,2,.......this sequence in arithmetic progression but this sequence is decreasing sequence.

given first term is 20 and difference is $d = second term- first term = 14-20=-6$

now the nth term of given sequence is

by using formula $t_{n}=a+(n-1)d$

$t_{n}= 20+(n-1)(-6)$

$t_{n}= 20-6 n+6$

final answer:-

$t_{n} = 26-6 n$

<u>verification</u>:-

$t_{n} = 26-6 n$

put n=1 we get first term is 20

put n=2 we get second term is 14

put n=3 we get third term is 8

put n=4 we get fourth term is 2

so the n th term of sequence is

$t_{n} = 26-6 n$

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3 years ago

Elijah earns $200 for 8 hours of work.What is the rate (in dollars per item)

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2 years ago

Janet has $75 to spend at the mall. She has already spent $28. She wants to buy games that cost $15 each, including tax. Enter t

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Answer:

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Step-by-step explanation:

The computation of the maximum number of games that he could buy is shown below:

= Amount available - already spent

= $75 - $28

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If each game cost $15

So, the maximum no of games is

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