The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Ronaldo has five times blancas amount
Juan has twice the amount
Plus blancas one times her amount that is 8 time blances amount. If Blanca has 1/8 of 500 then Juan has 1/4 and 1/4 of 500 is 125
Answer:
-2, -13
0, -3
2, 7
4, 17
Step-by-step explanation:
To fill out the table, substitute the table x-values into the equation and the y-values will fill the table.
y = 5x - 3
y = 5(-2) - 3
y = -10 - 3
y = -13
This means the table value corresponding to -2 should be -13.
y = 5x - 3
y = 5(0) - 3
y = 0 - 3
y = -3
This means the table value corresponding to 0 should be -3.
y = 5x - 3
y = 5(2) - 3
y = 10 - 3
y = 7
This means the table value corresponding to 2 should be 7.
y = 5x - 3
y = 5(4) - 3
y = 20 - 3
y = 17
This means the table value corresponding to 4 should be 17.
No,
although all the sides are the same length on an equilateral triangle the height is calculated by a straight perpendicular line at the mid point of the base.
The sides are not perpendicular with the base and are angled outwards
Answer:
4.472
Step-by-step explanation:
