Find the greatest possible number of consecutive zeros at the end of the product of three positive integers if the sum of these

Question

2 years ago

11

three integers equals 939.
(The number 202100 has exactly 2 consecutive zeros at the end.)

1 answer:

Romashka-Z-Leto [24] · Answer 1 · 2023-09-08T14:43:12+03:00

6 0

Answer:

A. Of first 100 multiples of 10

B. 5*10*15*20*25*30*35*40*40*45

C. 100!

I would also like to know whether this kind of question is possible in GMAT and what would be the complexity level.

1. 124

2. 10

3. 24