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frozen [14]
2 years ago
14

What’s the chord BC?

Mathematics
1 answer:
Mashutka [201]2 years ago
5 0

Answer:

  D)  3.8 cm

Step-by-step explanation:

There are several ways this problem can be solved. Maybe the easiest is to use the Law of Cosines to find angle BAC. Then trig functions can be used to find the length of the chord.

__

In triangle BAC, the Law of Cosines tells us ...

  a² = b² +c² -2bc·cos(A)

  A = arccos((b² +c² -a²)/(2bc)) = arccos((8² +6² -3²)/(2·8·6)) = arccos(91/96)

  A ≈ 18.573°

The measure of half the chord is AB times the sine of this angle:

  BD = 2(AB·sin(A)) ≈ 3.82222

The length of the common chord is about 3.8 cm.

_____

<em>Additional comment</em>

Another solution can be found using Heron's formula to find the area of triangle ABC. From that, its altitude can be found.

  Area ABC = √(s(s-a)(s-b)(s-c)) . . . . where s=(a+b+c)/2

  s=(3+8+6)/2 = 8.5

  A = √(8.5(8.5 -3)(8.5 -8)(8.5 -6)) = √54.4375 ≈ 7.64444

The altitude of triangle ABC to segment AC is given by ...

  A = 1/2bh

  h = 2A/b = 2(7.64444)/8 = 1.911111

BD = 2h = 3.822222

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We are given the functions:

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To find for the value of f(x) + g(x), all we have to do is to add equations 1 and 2:

f(x) + g(x) = 4 x – 5 + 3 x + 7

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625

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Step-by-step explanation:

I'm gonna assume that cm= compounded monthly

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x= payments

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6 0
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Step-by-step explanation:

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