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3 years ago

10

Condense the logarithm expression 100 points

2 answers:

Butoxors [25]3 years ago

7 0

Answer:

I agree with the person above me!

Step-by-step explanation:

(1/2)[logb(b^2)+logb(8x)]

=(1/2)[2+logb(8x)]

=1+(1/2)logb(8x)

lara [203]3 years ago

4 0

(1/2)[logb(b^2)+logb(8x)]

=(1/2)[2+logb(8x)]

=1+(1/2)logb(8x)

hope this helps you

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