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Murljashka [212]
3 years ago
7

Which is the equation of a line that has a slope of 2 and contains the point (0,5)

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
7 0

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=2(x-0) \\\\\\ y-5=2x\implies y=2x+5

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Step-by-step explanation:

The equation of that line in slope intercept form is y = -2/5x + 2

The slope of a line parallel to that line will be the same as its slope, so -2/5.

To find the y-intercept of a line that passes through the point (-5, 1) with that slope, you will have to plug in the x and y values of that point into what you know of the equation of the line.

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From this, you can construct an equation.

y = -2/5x - 1

However, this is not an answer choice.  

It cannot be A because this line does not have a slope of -1.

2x + 5y = 15

5y = -2x - 5

y = -2/5x - 1

It can be B because this line is the same as the equation we came up with.

It cannot be C because this line does not have a slope of -1 or a y-intercept of -3.

2x + 5y = -15

5y = -2x - 15

y = -2/5x - 3

It cannot be D because this line does not have a y-intercept of -3.

y - 1 = -2/5(x + 5)

y - 1 = -2/5x - 2

y = -2/5x - 1

It can be E because this equation matches the one we came up with.

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Step-by-step explanation:

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