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Ilia_Sergeevich [38]
3 years ago
12

What are the two factor of the the quadratic x^2 -10x-39?

Mathematics
1 answer:
VLD [36.1K]3 years ago
4 0

Answer:

(x-13)(x+3)

Step-by-step explanation:

Trinomials are three term algebraic expressions typically featuring variables to exponent powers. To break these trinomials down we factor them using the diamond method or GCF. The diamond method states that for a trinomial ax^2+bx+c multiply a*c then find two numbers which multiply to this number and add to b. When you find those numbers, write them as (x-/+ number)(x-/+number).

x^2-10x-39

a=1, c=-39

ac=-39 and add to b=-10 which -13 and 3 satisfy

(x-13)(x+3)


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In cases like this, we have to remember that a root is always positive, so we can square both sides only assuming that

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Under this assumption, we square both sides and we have

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The solutions to this equation are

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But since we can only accept solutions greater than -1, we discard x=-2 and accept x=1.

In fact, we have

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7 0
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SCORPION-xisa [38]
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asambeis [7]

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Step-by-step explanation:

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