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sasho [114]
3 years ago
12

In the equation x^2 mx n = 0, m and n are integers. The only possible value for x is –3. What is the value of m ?

Mathematics
1 answer:
sineoko [7]3 years ago
5 0
I am going to go with the assumption that your equation is x^2+mx+n=0. If there is only one solution, then the equation must be a perfect square. So square (x+3) to solve for the equation in the similar form that is given. (x+3)^2=x^2+6x+9=0. So the variables match up perfectly in the equation, meaning that the value of m is 6, letter choice C.
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