Question

In the equation x^2 mx n = 0, m and n are integers. The only possible value for x is –3. What is the value of m ?

Answer 1

I am going to go with the assumption that your equation is $x^2+mx+n=0$. If there is only one solution, then the equation must be a perfect square. So square $(x+3)$ to solve for the equation in the similar form that is given. $(x+3)^2=x^2+6x+9=0$. So the variables match up perfectly in the equation, meaning that the value of m is 6, letter choice C.