Question

Hello, please solve the following:

Answer 1

Answer:

1.) (1,2)  2.) (3,-1)

Explanation:

1.)  y - x = 1
y + 4x =6 {SUBSITUTION METHOD}
y - x = 1 , y = x + 1 |     y - 1 = 1 --> y = 2
y + 4x = 6 --> (x + 1) + 4x =6 --> 5x + 1 =6 --> 5x =5 --> x=1

2.) 2x + 3y = 3
3x - 6y = 15 {ELIMINATION METHOD}

4x + 6y = 6      4(3) + 6y = 6
3x - 6y = 15        6y + 12 = 6

7x         = 21               6y = -6

x = 3                             y = -1