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2 years ago

Can i get some help, please

Mathematics

2 answers:

RoseWind [281]2 years ago

6 0

Answer:

65 degrees

Step-by-step explanation:

The degrees always has to add up to 180 degrees, so if you add 90 degrees and 25 degrees, you get 115 degrees. So since it has to be 180 degrees, you add 65 to 115, and you get 180 degrees.

maxonik [38]2 years ago

3 0

Answer: 65 degrees . HOPE IT HELPS .

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120 students voted for Jennifer and 180 students voted for Kevin. 60 students voted more for Kevin than for Jennifer.

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3 years ago

If f(x)=2x^3-x+c and f(2)=10 then what's the value of c?

Goshia [24]

Answer:

c = -4

Step-by-step explanation:

If f(x) = 2x^3 - x + c and f(2) = 10, plug in 2 for the x values in the function and make the function output 10.

10 = 2(2^3) - 2 + c Now, we only have to deal with one variable, that is c.

10 = 2(8) - 2 + c

10 = 16 - 2 + c

10 = 14 + c

-4 = c After simplifying, we get that c is -4.

To check this, plug in 2 for x, and -4 for c in the function. If the function produces 10 as the result, the halleluja!

f(2) = 2(2^3) - 2 - 4

f(2) = 2(8) - 2 - 4

f(2) = 16 - 2 - 4

f(2) = 10

7 0

3 years ago

Read 2 more answers

Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

7 0

3 years ago

2n - n+5=3 help please

Doss [256]

n=-2 i got this answer because i combined like terms first like 2n-n

we get just n after

and then, we subtract the 5 from both sides to get it on the opposite side of the equal sign.. we get x=-2

5 0

3 years ago