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2 years ago

13

HELPPP ASAP PLEASE THE QUESTION IS “ Which equation represents the sentence “the quotient of z and 7 is 9” PLEASE HELP I NEED IT

RIGHT NOW ITS A QUIZZZZZZZZZZZZ!!!!!!!!!!!!!!!!!!!!!THE PICTURE ARE THE OPTIONS

2 answers:

Grace [21]2 years ago

4 0

I can’t see the while question, can you please zoom out?.

weeeeeb [17]2 years ago

4 0

Answer:

C.

(z/7) = 9

Step-by-step explanation:

Quotient means divide, so it's not D. It also reads (is 9), meaning (= 9). So it's not A. That leaves B and C left. All that's really left is to put the numbers in order. In this case z, and then 7. That leaves us with C.

(sorry if this is wordy or hard to understand)

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Determine if the pair of ratios or rates are equivalent.

Norma-Jean [14]

Yes because $18 divided by 3 bracelets makes the price per bracelet $6. $30 divided by 5 bracelets makes the price per bracelet $6. The cost per bracelet is the same so the cost to bracelet ratio is the same and both are a $6 to 1 bracelet ratio

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3 years ago

The statement ‘5 is added to 9 times a certain number n and the result is 32’ is represented by? *

salantis [7]

Answer:

5+(9×n)=32

n=3

.:.n is represented by 3

3 0

2 years ago

I need help writing the first 5 terms of the sequence!

Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

$a_{1}=1$

$a_{n}=a_{n-1}+3$

General term of the arithmetic sequence.

$a_{n}=a_{n-1}+d$ , where d is the common difference.

d = 3

$a_{n}=a_{n-1}+3$

Put n = 2 in $a_{n}=a_{n-1}+3$ , we get

$a_{2}=a_1+3$

$a_{2}=1+3$

$a_2=4$

Put n = 3 in $a_{n}=a_{n-1}+3$ , we get

$a_{3}=a_2+3$

$a_{3}=4+3$

$a_3=7$

Put n = 4 in $a_{n}=a_{n-1}+3$ , we get

$a_{4}=a_3+3$

$a_{4}=7+3$

$a_4=10$

Put n = 5 in $a_{n}=a_{n-1}+3$ , we get

$a_{5}=a_4+3$

$a_{5}=10+3$

$a_5=13$

The first five terms of the sequence are 1, 4, 7, 10, 13.

3 0

3 years ago

Please help. Question is in the picture

kumpel [21]

Number 4: line XZ; number 5: theory of congruent triangles.

4 0

2 years ago

What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.

Paul [167]

Answer:

1.60 $ft^{2}$

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = $\pi$ $r^{2}$

So that,

for the inner part of the pipe,

r = $\frac{diameter}{2}$

= $\frac{5}{2}$

= 2.5 feet

Area of the inner part of the pipe = $\pi$ $r^{2}$

= 3.14 x $(2.5)^{2}$

= 19.625

Are of the inner part of the pipe is 19.63 $ft^{2}$ .

Total diameter of the pipe = 5 + 0.2

= 5.2 feet

r = $\frac{5.2}{2}$

= 2.6 feet

Area of the pipe = $\pi$ $r^{2}$

= 3.14 x $(2.6)^{2}$

= 21.2264

Area of the pipe is 21.23 $ft^{2}$ .

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

= 21.2264 - 19.625

= 1.6014

The cross sectional area of the cement pipe is 1.60 $ft^{2}$ .

6 0

2 years ago