Given that plane P is parallel to the planes containing the base faces of the prism; then, if the plane meets the prism between the planes containing the hexagonal bases, then P meets the prism in a hexagonal region that is congruent (with the same size) to the bases of the prism.
Answer:
wish i could help tbh
Step-by-step explanation:
Answer:
.
Step-by-step explanation:
Answer:
-20/13 <g
Step-by-step explanation:
-7–5(3g+8)<10g–7+g
Distribute
-7–15g-40<10g–7+g
Combine like terms
-15g - 47 < 11g -7
Add 15 g to each side
-15g+15g -47< 11g+15g -7
-47 < 26g -7
Add 7 to each side
-47+7 < 26g-7+7
-40 < 26g
Divide each side by 26
-40/26 <26g/26
-40/26 <g
Divide top and bottom by 2
-20/13 <g
Answer:
0
Step-by-step explanation:
Distance between two points is the slope .
Slope =change in y/change in x
Given (-26,0) and (95,0)
x1 = -26
y1 = 0
x2 = 95
y2 = 0
Slope = y2 - y1 / x2 - x1
0-0/95-(-26)
0-0/95+26
0/121
0
