Answer:
11 units
Step-by-step explanation:
The height of a trapezoid is the distance between the parallel bases.
__
Here, one base lies on the horizontal line y=5, and the other lies on the horizontal line y = -6. The distance between them is ...
5 -(-6) = 5 +6 = 11
You can also find this distance by counting the grid squares between the two parallel lines.
The height of the trapezoid is 11 units.
_____
<em>Additional comment</em>
The base lengths are ...
AB = 2 -(-5) = 7
CD = 8 -(-7) = 15
The area is 1/2(b1 +b2)h = (1/2)(7 +15)(11) = 121 square units.
Answer:
A: The x-intercept of k(x) is half the x-intercept of h(x)
Step-by-step explanation:
Answer choices B, C, and D are concerned with slopes and y-intercepts. The coefficients of x in the functions are different and are related by a factor of -2, so the lines are not parallel, and one slope is not twice the other. The y-intercepts (constants) in each function are different, so they graphs do not cross the y-axis at the same place.
Hence answer choices B, C, and D can be eliminated.
The x-intercepts are found by setting y=0 and solving for x:
h(x) = 0 = -2x +4 ⇒ x = 4/2 = 2
k(x) = 0 = 4x -4 ⇒ x = 4/4 = 1
The x-intercept of k(x) is half that of h(x). . . . . . . matches choice A
Http://www.tiger-algebra.com/drill/5~5x-1=6~3x/ hope this works
Arc SCD is two times of angle SED, so arc SCD is 8x+22. Now set 8x+22, 5x-8, and 11x+10 to 360 and solve for x
A) (5s + 2 / 4) x (4) = Perimeter
B) ( s + 9) x (2) + ( 3s - 5 ) x (2) = Perimeter
C) 22 + 48 = 70