Given
class charlie records the volume of a liquid as 13.3 milliliters.
the actual volume is 13.6 milliliters
Find the percent error.
To proof
Formula
![Percentage\ error = \frac{error\times 100}{accepted\ value}](https://tex.z-dn.net/?f=Percentage%5C%20error%20%3D%20%5Cfrac%7Berror%5Ctimes%20100%7D%7Baccepted%5C%20value%7D)
error = accepted value - measured value
As given in the question
actual volume = 13.6 milliliters
records the volume of a liquid = 13.3 milliliters
error = actual volume - records volume
= 13 .6 - 13.3
= 0.3 milliliters
put all the value in the above formula
we get
![percent\ error = \frac{0.3\times100}{13.6}](https://tex.z-dn.net/?f=percent%5C%20error%20%3D%20%5Cfrac%7B0.3%5Ctimes100%7D%7B13.6%7D)
on solving the above equation
![percentage\ error = \frac{30}{13.6}](https://tex.z-dn.net/?f=percentage%5C%20error%20%3D%20%5Cfrac%7B30%7D%7B13.6%7D)
therefore
percentage error = 2.21 %
Hence proved
A, B, D, E, and I think F is right. C is not because a variable cannot be squarerooted.
Answer:
D
Step-by-step explanation:
Since KL = JL then the triangle is isosceles with base angles congruent, that is
∠ K = ∠ J = 8x + 5
The sum of the 3 angles in the triangle = 180°
sum the angles and equate to 180
8x + 5 + 8x + 5 + 5x - 19 = 180
21x - 9 = 180 ( add 9 to both sides )
21x = 189 ( divide both sides by 21 )
x = 9
Then
∠ J = 8x + 5 = 8(9) + 5 = 72 + 5 = 77°