What is the nth term rule of 7,9,11,13,15

Mathematics

2 answers:

sweet-ann [11.9K]2 years ago

8 0

Answer:

$a_{n}$ = 2n + 5

Step-by-step explanation:

There is a common difference between consecutive terms, that is

9 - 7 = 11 - 9 = 13 - 11 = 15 - 13 = 2

This indicates the sequence is arithmetic with nth term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 7 and d = 2 , then

$a_{n}$ = 7 + 2(n - 1) = 7 + 2n - 2 = 2n + 5

Juliette [100K]2 years ago

5 0

The answer is twenty three

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What are these numbers in order from greatest to least

DerKrebs [107]

Answer : Square root of 21 , -4 2/3, -30/7 , -31/6 .

Explanation :

-4 2/3 = -10/3 = -3.3333
Square root of 21 = 4.58258
-31/6 = -5.1666
-30/7 = 4.2857

And arrange them from greatest to least and there we have the answer.

Hope this helps you understand !!!!

4 0

3 years ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$