The first three terms of sequence are 9 , 6 , 3
<em><u>Solution:</u></em>
Given the recursive function f(n) = f(n - 1) - 3
Where f(1) = 9
To find: First three terms of sequence
Substitute n = 2 , n = 3 and n = 4 in given recursive function
When n = 2
f(n) = f(n - 1) - 3
f(2) = f(2 - 1) - 3
f(2) = f(1) - 3
f(2) = 9 - 3 = 6
f(2) = 6
Thus second term is 6
When n = 3
f(3) = f( 3 - 1) - 3
f(3) = f(2) - 3
f(3) = 6 - 3 = 3
f(3) = 3
Thus the third term is 3
When n = 4
f(4) = f( 4 - 1) - 3
f(4) = f(3) - 3
f(4) = 3 - 3
f(4) = 0
Thus the fourth term is 0
Thus first three terms of sequence are 9 , 6 , 3
1/2 is the slope of the following when you simplify
If LaTeX: P\left(6,-2\right),\:Q\left(-2,\:8\right),\:R\left(-4,\:3\right),\:P ( 6 , − 2 ) , Q ( − 2 , 8 ) , R ( − 4 , 3 ) ,and
Burka [1]
Answer:
<h3>y = -1</h3>
Step-by-step explanation:
First let us get the slope of the line PQ and RS
For PQ;
Given P(6, -2) and Q(-2,8)
slope m = 8-(-2)/-2-6
slope of pQ = 10/-8
slope of PQ = -5/4
For RS
R ( − 4 , 3 ) and S(-9, y)
slope of RS = y-3/-9+4
slope of RS = y-3/-5
For PQ to be perpendicular to RS, the product of their slope must be -1
Hence -5/4 (y-3/-5) = -1
y-3/4 = -1
cross multiply
y-3 = -4
y = -4+3
y = -1
Hence the value of y for PQ to be perpendicular to RS is -1
Answer:
(B)16
Step-by-step explanation:
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