3 years ago

What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?

Mathematics

2 answers:

Luba_88 [7]3 years ago

6 0

Answer:

k =3

Step-by-step explanation:

f(x) = 112 -kx

Let x = -3

f(-3) =112 -k(-3)

We know that it equals 121

121 = 112 +3k

Subtract 112 from each side

121-112 =112 -112 +3k

9 = 3k

Divide each side by 3

9/3 = 3k/3

3 =k

Ksenya-84 [330]3 years ago

4 0

Answer:

hello :

put - 3 in f(x) you have : 112 - k(-3) = 121

solve 112 +3k =121

3k = 121 -112

3k = 9

k = 3

Step-by-step explanation:

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