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svetlana [45]
3 years ago
11

What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?

Mathematics
2 answers:
Luba_88 [7]3 years ago
6 0

Answer:

k =3

Step-by-step explanation:

f(x) = 112 -kx

Let x = -3

f(-3) =112 -k(-3)

We know that it equals 121

121 = 112 +3k

Subtract 112 from each side

121-112 =112 -112 +3k

9 = 3k

Divide each side by 3

9/3 = 3k/3

3 =k

Ksenya-84 [330]3 years ago
4 0

Answer:

hello :

put - 3 in f(x) you have : 112 - k(-3) = 121

solve 112 +3k =121

3k = 121 -112

3k = 9

k = 3

Step-by-step explanation:


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Answer:

$14.4

Step-by-step explanation:

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3 years ago
What four factors were used to create this product game board 9,15,18,21,30,35,36,42,49
IgorLugansk [536]
To see what are the factors use, we write each of the numbers, as product of prime factors:

9= 3 \cdot 3\\\\
15=3 \cdot 5\\\\
18= 2 \cdot 9 = 2 \cdot 3 \cdot3\\\\21= 3\cdot 7\\\\30=3 \cdot10=3 \cdot 2 \cdot 5\\\\35=5 \cdot7\\\\36=6\cdot6=2\cdot3\cdot2\cdot3\\\\42=6\cdot7=2\cdot3\cdot7\\\\49=7\cdot7


As we can see, the 4 factors used to produce the numbers in the list are {2, 3, 5, 7}


Answer:  {2, 3, 5, 7}
5 0
3 years ago
Read 2 more answers
the sum of two numbers is 57. if the larger of the two numbers is 9 less than twice the smaller, find the two numbers
svp [43]

Answer:

The answer is 35 and 22

Because:

U let the numbers(#) be x and y (x will be the larger number and y the smaller number

So:

x + y =57

x = 2*y - 9

Therefore,

{2*y - 9} + y = 57

Leaving the two numbers 35 and 22

I hope I could help




7 0
3 years ago
Please help me thanks
Oliga [24]

Answer:

3

Step-by-step explanation:

equation, y=3x, because when x is 1, y is 3, so the equation is y=3x, and the slope is equal to how much of x is equal to y, so 3

Pls brainliest

3 0
2 years ago
Read 2 more answers
A concert hall has 8,000 seats and two categories of ticket prices, $29 and $34. Assume that all seats in each category can be s
Greeley [361]

Using a system of equations, it is found that:

  • For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
  • For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
  • For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

--------------------

The variables of the system are:

  • x, which is the number of $29 tickets sold.
  • y, which is the number of $34 tickets sold.

Total of 8,000 seats, all can be sold, thus:

x + y = 8000 \rightarrow x = 8000 - y

--------------------

For a profit of $255,000, we have that:

29x + 34y = 255000

29(8000 - y) + 34y = 255000

5y = 23000

y = \frac{23000}{5}

y = 4600

x = 8000 - 4600 = 3400

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.

--------------------

For a profit of $271,000, we have that:

29x + 34y = 271000

29(8000 - y) + 34y = 271000

5y = 39000

y = \frac{39000}{5}

y = 7800

x = 8000 - 7800= 200

For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.

--------------------

For a profit of $235,000, we have that:

29x + 34y = 235000

29(8000 - y) + 34y = 235000

5y = 3000

y = \frac{3000}{5}

y = 600

x = 8000 - 600 = 7400

For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

A similar problem is given at brainly.com/question/22826010

3 0
3 years ago
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