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4 years ago

A cells membrane is composed of two layers of lipid molecules what is the function of a cell membrane

Biology

1 answer:

andrey2020 [161]4 years ago

6 0

It selectively controls what goes in and out of the cell

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14 points

Wewaii [24]

Answer:

the answer is height above the sea level pls mark me as the brainliset hope it helps you

5 0

3 years ago

ASAP - BRAINLIEST TO BEST ANSWER:

gregori [183]

Answer:

Preserving the habitat of an endangered species is important to its protection. Little brown bats live in a wide range of habitats. They live in forests and mountains, and even form colonies in buildings, attics, and other artificial structures that humans could be affecting. Sadly, many bats are under severe threat from increasing human pressure. Habitat loss, climate change, roost destruction, disease, deforestation, guano mining, disturbance and persecution, and increasing numbers of wind farms are all causes of bats declining because of us.

Explanation:

I hope this helps! :}

5 0

3 years ago

The last common ancestor of all animals was probably a ________.

lutik1710 [3]

Ape, Monkey or Gorilla

3 0

3 years ago

How do thick and fleshy leaves of aloe Vera helps in adaptation

Simora [160]

Answer:

Aloes adapt to this by using their tissue to store large volumes of water. Aloe vera has thick and fleshy leaves, which are enlarged to accommodate the aqueous tissue. ... Carbohydrates synthesized in excess of that needed for energy are transported by the phloem to the cells in the leaf pulp.

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7 0

3 years ago

Cystic fibrosis is an autosomal recessive disorder. In one population, the frequency of affected individuals (A 2 A 2) is 0.0004

Simora [160]

Hardy Weinberg Equilibrium

Explanation:

Hardy Weinberg Equilibrium formula for allelic frequency is: $p+q=1$

Hardy Weinberg Equilibrium formula for genotypic frequency is: $p^2+q^2+2pq=1$

Here, $p$ =frequency of dominant allele

$q$ =frequency of recessive allele

$p^2$ =frequency of dominant genotype

$q^2$ =frequency of recessive genotype

$2pq$ =frequency of heterozygous genotype

frequency of affected individuals=0.0004(given)

here,affected individuals means the one's having Cystic Fibrosis and since it is recessive disease so we can write frequency of recessive genotype as: $q^2$ =0.0004

If $q^2$ =0.0004 $q$ will be 0.02;frequency of recessive allele will be 0.02

Using the formula $p+q=1$

$p+0.02=1\\p=1-0.02=0.98$

hence,frequency of dominant allele will be 0.98

Frequency of dominant genotype will be $p^2=(0.98)^2=0.9604$
Frequency of heterozygous genotype will be $2pq=2*0.98*0.02=0.0392$

7 0

4 years ago