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Citrus2011 [14]
1 year ago
5

Select the correct answer.

Mathematics
1 answer:
Elena L [17]1 year ago
5 0

Answer:

Step-by-step explanation:

The correct answer of this question is B

All you need is multiply it by 6

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Explain plz!!! Explain
ycow [4]

Answer: the answer is 8 rows


Step-by-step explanation: If there are 112 students and they need to be put in rows of 14 you must divide 112 by 14 to get the amount of rows.


7 0
3 years ago
Need help with all And have to show work
kari74 [83]
Altho' I can easily guess what you're supposed to do here, I must point out that you haven't included the instructions for this problem.

I'll help you by example.  Let's look at the first problem:

"Evaluate  6(z-1) at z-4."

Due to "order of operations" rules, we must do the work inside the parentheses FIRST.  Replace the z inside (z-1) with "-4".  We obtain

6(-4-1) = 6(-5) = -30 (answer.)

Your turn.  Try the next one.  If it's unclear, as questions.
8 0
3 years ago
25% of €40:00 = €<br> And explain it
Wewaii [24]

Answer:

The correct answer is €10.00

Step-by-step explanation:

50% of 40 is 20. 50% of 50 is 25, so what you do is just take 20 and multiply that by 0.5 or you can just take 40 and multiply that by 0.25.

I really hope this helps you out!

5 0
2 years ago
Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.
Aleks [24]

Answer:

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

Step-by-step explanation:

The actual Series is::

\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}

The method we are going to use is comparison method:

According to comparison method, we have:

\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}

Now:

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty}  \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

\sum_{n=1}^{inf}\frac{1}{n^p}

if p>1 then series converges. In oue case we have:

\sum_{n=1}^{inf}b_n=\frac{1}{n^4}

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

5 0
3 years ago
Are total emissions or per-capita emissions a better gauge when comparing the co2 emissions of various countries? why? emissions
algol13

The emissions per capita measurement is a better because it shows the number of people divided by the emissions.

<h3>What is the difference between total emissions and emissions per capita?</h3>

The emissions per capita show the emissions per each citizen or inhabitant, while the total emissions show only the emissions of the country.

<h3>Which one is better?</h3>

The per capita gauge is better because whether a country is polluting more or not depends on how much each citizen pollutes. This information is useful to create laws that reduce pollution.

Learn more about pollution in: brainly.com/question/23857736

#SPJ1

4 0
1 year ago
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