Answer:
Death Valley California
C(t) = -0.30 (0)² + 40
C(t) = 40
C(t) = -0.30 (12)² + 40t – 12)2 + 40
65f
The coefficient is 2 (it is always the number before the variable)
Answer:
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error of the interval is given by:

In this problem, we have that:

99.5% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?
This is n when M = 0.07. So







A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Answer:
A B C
Step-by-step explanation:
Let A,B and C be the number of seats in section A,B and respectively. The situation can be represented by the following system. 1. A+B+C=49,000 2. 25A+20B+50C=1,052,000 and 3. A=B+C
Answer:
25
Step-by-step explanation:
5:20
We want to get the second number to 100
100/20 = 5
Multiply each term by 5
5*5 : 20*5
25 : 100
x is 25