Which expression represents 10 times the sum of a number and 4?

To what extent were the goals of reconstruction regarding african-americans achieved by 1900?.

Gemiola [76]

Answer: The goals were

ensure citizenship and civil liberties , Provide economic , and Provide education opportunities for former slaves

Explanation:civil right act in 1866

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Explanation:

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3 years ago

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Which of the following statements about the lambert projection is (are) true.

Natali5045456 [20]

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You need to give the statements

Explanation:

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This forms the basis of all extruded parts.

egoroff_w [7]

Answer:

i think it would be c?

Explanation:

3 0

3 years ago

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Lammps ERROR on proc 0: Out of range atoms - cannot compute PPPM

Alexeev081 [22]

Using the knowledge in computational language in C++ it is possible to write a code that Out of range atoms:

<h3>Writting the code in C++:</h3>

#include <cmath>

#include "pppm_tip4p.h"

#include "atom.h"

#include "domain.h"

#include "force.h"

#include "memory.h"

#include "error.h"

#include "math_const.h"

using namespace LAMMPS_NS;

using namespace MathConst;

#define OFFSET 16384

#ifdef FFT_SINGLE

#define ZEROF 0.0f

#define ONEF 1.0f

#else

#define ZEROF 0.0

#define ONEF 1.0

#endif

void PPPMTIP4P::init()

{

// TIP4P PPPM requires newton on, b/c it computes forces on ghost atoms

if (force->newton == 0)

error->all(FLERR,"Kspace style pppm/tip4p requires newton on");

PPPM::init();

}

void PPPMTIP4P::particle_map()

{

int nx,ny,nz,iH1,iH2;

double *xi,xM[3];

int *type = atom->type;

double **x = atom->x;

int nlocal = atom->nlocal;

if (!std::isfinite(boxlo[0]) || !std::isfinite(boxlo[1]) || !std::isfinite(boxlo[2]))

error->one(FLERR,"Non-numeric box dimensions - simulation unstable");

int flag = 0;

for (int i = 0; i < nlocal; i++) {

if (type[i] == typeO) {

find_M(i,iH1,iH2,xM);

xi = xM;

} else xi = x[i];

nx = static_cast<int> ((xi[0]-boxlo[0])*delxinv+shift) - OFFSET;

ny = static_cast<int> ((xi[1]-boxlo[1])*delyinv+shift) - OFFSET;

nz = static_cast<int> ((xi[2]-boxlo[2])*delzinv+shift) - OFFSET;

part2grid[i][0] = nx;

part2grid[i][1] = ny;

part2grid[i][2] = nz;

if (nx+nlower < nxlo_out || nx+nupper > nxhi_out ||

ny+nlower < nylo_out || ny+nupper > nyhi_out ||

nz+nlower < nzlo_out || nz+nupper > nzhi_out) flag++;

}

int flag_all;

MPI_Allreduce(&flag,&flag_all,1,MPI_INT,MPI_SUM,world);

if (flag_all) error->all(FLERR,"Out of range atoms - cannot compute PPPM");

}

void PPPMTIP4P::make_rho()

{

int i,l,m,n,nx,ny,nz,mx,my,mz,iH1,iH2;

FFT_SCALAR dx,dy,dz,x0,y0,z0;

double *xi,xM[3];

FFT_SCALAR *vec = &density_brick[nzlo_out][nylo_out][nxlo_out];

for (i = 0; i < ngrid; i++) vec[i] = ZEROF;

int *type = atom->type;

double *q = atom->q;

double **x = atom->x;

int nlocal = atom->nlocal;

for (int i = 0; i < nlocal; i++) {

if (type[i] == typeO) {

find_M(i,iH1,iH2,xM);

xi = xM;

} else xi = x[i];

nx = part2grid[i][0];

ny = part2grid[i][1];

nz = part2grid[i][2];

dx = nx+shiftone - (xi[0]-boxlo[0])*delxinv;

dy = ny+shiftone - (xi[1]-boxlo[1])*delyinv;

dz = nz+shiftone - (xi[2]-boxlo[2])*delzinv;

compute_rho1d(dx,dy,dz);

z0 = delvolinv * q[i];

for (n = nlower; n <= nupper; n++) {

mz = n+nz;

y0 = z0*rho1d[2][n];

for (m = nlower; m <= nupper; m++) {

my = m+ny;

x0 = y0*rho1d[1][m];

for (l = nlower; l <= nupper; l++) {

mx = l+nx;

density_brick[mz][my][mx] += x0*rho1d[0][l];

}

}

See more about C++ at brainly.com/question/19705654

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6 0

2 years ago