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Aleks04 [339]
2 years ago
7

100 points

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
3 0
STEP
1
:

y
Simplify —
3
Equation at the end of step
1
:

y
(((18•(x5))•(y3))+((6•(x2))•(y4)))+((((24•(x6))•—)•x)•y)
3
STEP
2
:

Equation at the end of step
2
:

y
(((18•(x5))•(y3))+((6•(x2))•(y4)))+((((23•3x6)•—)•x)•y)
3
STEP
3
:

Canceling Out:

3.1 Canceling out 3 as it appears on both sides of the fraction line


Equation at the end of step
3
:

(((18•(x5))•(y3))+((6•(x2))•(y4)))+((8x6y•x)•y)
STEP
4
:

Equation at the end of step
4
:

(((18•(x5))•(y3))+((2•3x2)•y4))+8x7y2
STEP
5
:

Equation at the end of step
5
:

(((2•32x5) • y3) + (2•3x2y4)) + 8x7y2
STEP
6
:

STEP
7
:
Pulling out like terms

7.1 Pull out like factors :

8x7y2 + 18x5y3 + 6x2y4 = 2x2y2 • (4x5 + 9x3y + 3y2)

Trying to factor a multi variable polynomial :

7.2 Factoring 4x5 + 9x3y + 3y2

Try to factor this multi-variable trinomial using trial and error

Factorization fails

Final result :
2x2y2 • (4x5 + 9x3y + 3y2)
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NeTakaya

Answer:

5 tractors can plow a square field of side length 1,000 meters in 3.33 hours (3 hours 20 minutes)

Step-by-step explanation:

Let's find out how much each tractor can plow each hour.

\frac{600^{2} }{3*2}=60,000m^{2} per tractor per hour

1,000^{2}=1,000,000m^{2} is the area of the field of side length 1,000 meters

5 tractors can plow 300,000m^{2} per hour.

\frac{1,000,000}{300,000}=3.33 hours

8 0
3 years ago
What is the actual length of the living space if the length of the scale drawing is 16.8 centimeters? Enter your answer in the b
algol13
<h2>Answer:</h2><h2></h2><h3>21m</h3><h2></h2><h2>Explanation:</h2><h2></h2>

The diagram and complete question is shown below. We know that the length (L) of the living scale in the drawing is:

L=16.8cm

We also know that the scale is:

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Then, by using proportion we have:

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4 years ago
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Answer:

Correct answer would be 84/12=7

Step-by-step explanation:

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Answer:

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irinina [24]
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(11/4)*3=
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