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2 years ago

What is the slope intercept of 3x-2y=-16.

Mathematics

1 answer:

nikklg [1K]2 years ago

4 0

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$\diamond\large\blue\textsf{\textbf{\underline{Given question:-}}}$

What is the slope-intercept form of 3x-2y=-16?

$\diamond\large\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}$

✥ First, we need to subtract 3x on both sides, which results in

-2y=-16-3x

-2y=-3x-16

$\bigstar$ Now, divide by -2 on both sides:-

$\bold{(-2y):-2=(-3x-16):-2}$

On simplification,

$\bold{y=\dfrac{3}{2} x+8}$

<h3>Good luck with your studies.</h3>

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Patrick wants to play laser tag. It costs $9.00 per game and he gets a student discount of $10. Write an equation to represent t

Nana76 [90]

Answer:

$T=9x-10$

Step-by-step explanation:

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3 years ago

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Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...