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yanalaym [24]
3 years ago
7

Which angles seem to be congruent?

Mathematics
1 answer:
Anna007 [38]3 years ago
6 0

Answer:

angles 1, 4, 5, and 8 and angles 2, 3, 6, and 7

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Marcus solved for x in the quadratic equation x2 – 10x + 25 = 0.
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1 ,3 and 4 are correct :)
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Y=−4x−3 y=−2x+1 ​solve by graphing
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Answer: (-2,5)

Step-by-step explanation: just graph both equations they are already set up in the form and find the point where they intersect

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Evaluate summation of negative quantity n minus 5 end quantity from n equals 2 to 8
nydimaria [60]
One way of doing it is by using the properties of summing things, like factoring out the minus sign: <span><span>∑<span>n=2</span>8</span><span>−(n−5)</span>=−<span>∑<span>n=2</span>8</span><span>(n−5)


</span></span> and splitting it up into two parts and again factor <span>=−<span>(<span><span>∑<span>n=2</span>8</span><span>n−5<span>∑<span>n=2</span>8</span>1</span></span>)


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<span><span>∑<span>n=1</span>m</span>n=<span><span>m(m+1)</span>2


</span></span> So what we get is <span><span>=−<span>(<span>−1+<span><span>8(8+1)</span>2</span>−7</span>)</span>=8−72/2=8−36=−28.</span></span>
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7. Use the following figure to answer questions a-d.
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3 years ago
a cuboid with a volume of 924 cm3 has dimensions 4cm (x+1)cm and (x+11)cm. show clearly that x^2 +12x-220=0. show the equation b
nikdorinn [45]

Answer:

Part 1)

The equation by factorization is

x^{2}+12x-230=(x-(-6+\sqrt{266}))(x-(-6-\sqrt{266}))

Both values of x are

x1=-6+\sqrt{266}

x2=-6-\sqrt{266}

Part 2) The dimensions of the cuboid are

4\ cm, (-5+\sqrt{266})\ cm and (5+\sqrt{266})\ cm

Step-by-step explanation:

step 1

we know that

The volume of the cuboid is equal to

V=LWH

substitute the given values

V=4(x+1)(x+11)

V=924\ cm^{3}

so

4(x+1)(x+11)=924\\4(x^{2}+11x+x+11)=924\\ 4(x^{2}+12x+11)=924\\x^{2}+12x+11=231\\x^{2}+12x-230=0

Complete the square

x^{2}+12x-230=0

x^{2}+12x=230

x^{2}+12x+36=230+36

(x+6)^{2}=266

square root both sides

x+6=(+/-)\sqrt{266}

x=-6(+/-)\sqrt{266}

so

x1=-6+\sqrt{266}

x2=-6-\sqrt{266}

therefore

The equation by factorization is

x^{2}+12x-230=(x-(-6+\sqrt{266}))(x-(-6-\sqrt{266}))

step 2

Find the dimensions of the cuboid

The dimensions are

4\ cm

(x+1)\ cm -----> (-6+\sqrt{266}+1)=(-5+\sqrt{266})\ cm

(x+11)\ cm ----> (-6+\sqrt{266}+11)=(5+\sqrt{266})\ cm

4 0
3 years ago
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