Question

Which equation has the solutions x = startfraction negative 3 plus-or-minus startroot 3 endroot i over 2 endfraction? 2x2 6x 9 = 0 x2 3x 12 = 0 x2 3x 3 = 0 2x2 6x 3 = 0

Answer 1

The quadratic equation which matches given solution is x² + 3x + 3 = 0. Then the correct option is C.

What is a quadratic equation?

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.

We know that the formula

$\rm x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

The solutions are given below.

$\rm x = \dfrac{-3 \pm \sqrt3 \iota }{2}$

Then

1)  2x² + 6x + 9 = 0, the zeroes of the equation will be

$\rm x = \dfrac{-6\pm 6\iota}{4}\\\\x = \dfrac{-3\pm 3 \iota}{2}$

2)  x² + 3x + 12 = 0, the zeroes of the equation will be

$\rm x = \dfrac{-3\pm \sqrt{39}\iota}{2}$

3)  x² + 3x + 3 = 0, the zeroes of the equation will be

$\rm x = \dfrac{-3\pm \sqrt3\iota}{2}$

4)  2x² + 6x + 3 = 0, the zeroes of the equation will be

$\rm x = \dfrac{-6\pm 2\sqrt{3}}{4}\\\\x = \dfrac{-3\pm \sqrt3 }{2}$

More about the quadratic equation link is given below.

brainly.com/question/2263981