Answer:
the relation between them are
n(U) = n(X U Y) + n(xūy).
Answer:

Step-by-step explanation:
Lets use the compound interest formula provided to solve this:

<em>P = initial balance</em>
<em>r = interest rate (decimal)</em>
<em>n = number of times compounded annually</em>
<em>t = time</em>
First, change 6% into a decimal:
6% ->
-> 0.06
Since the interest is compounded semi-annually, we will use 2 for n. Lets plug in the values now and your equation will be:

The answer to your question is a=124 because the center triangle is a isosceles triangle
Answer:
Step-by-step explanation:
Alright, lets get started.
The given equation is :

taking log on both side


Plugging the value of ln e as 1

Subtracting 6 in both sides


Dividing 3 in both sides
........................ Answer
Hope it will help :)
Answer:
Some number that are multiples of three are also even numbers
Step-by-step explanation:
In the picture