Hello,

Let's assume

$t=z- \dfrac{1}{z} \\\\

t^2=z^2-2+ \dfrac{1}{z^2}= 11-2=9==\ \textgreater \ t=3\\\\

t^3=z^3-3z^2* \dfrac{1}{z} +3z* \dfrac{1}{z^2} - \dfrac{1}{z^3} \\\\
=z^3 - \dfrac{1}{z^3} -3(z-\dfrac{1}{z})\\\\
z^3 - \dfrac{1}{z^3}=t^3+3t=3^3+9=27+9=36


$

7 0

3 years ago

I need help with this problem please! It's very confusing to me.

Daniel [21]

2.25X5= 11.25

2 1/4 turns into 2.25 as a decimal, and a pentagon has 5 equal sides, so you take 2.25 and multiply it by 5 to get your answer

11.25ft

4 0

3 years ago

Pls help not to sure on this one

skad [1K]

The answer is A. U basically divide the price with the amount of item and pick the cheapest one :)

3 0

3 years ago