Answer:
The probability that Scott will wash is 2.5
Step-by-step explanation:
Given
Let the events be: P = Purple and G = Green


Required
The probability of Scott washing the dishes
If Scott washes the dishes, then it means he picks two spoons of the same color handle.
So, we have to calculate the probability of picking the same handle. i.e.

This gives:










<em>Note that: 1 is subtracted because it is a probability without replacement</em>
So, we have:





Each member of the team will get two thirds of an orange.
Simplify the following:
sqrt(378904)
sqrt(378904) = sqrt(8×47363) = sqrt(2^3×47363):
sqrt(2^3 47363)
sqrt(2^3 47363) = sqrt(2^3) sqrt(47363) = 2 sqrt(2) sqrt(47363):
2 sqrt(2) sqrt(47363)
sqrt(2) sqrt(47363) = sqrt(2×47363):
2 sqrt(2×47363)
2×47363 = 94726:
Answer: 2 sqrt(94726)
The measure of the third angle is 50 because a triangle has a sum of 180 degrees by angle.
so... 46+84=130 and to get to 180, the last angle has to be worth 50.
The answer is 0 unless I did the math wrong
If so someone correct me. Other than that, hope this helped!