The equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3
The line is passing through the point = (-6,-3)
The slope of the line = 0
The point slope form is

Substitute the values in the equation
(y-(-3)) = 0×(x-(-6))
We have to convert this equation the slope intercept form
Slope intercept form is
y = mx + b
Where m is the slope of the line
b is the y intercept
(y-(-3)) = 0×(x-(-6))
y+3 = 0×(x+6)
y+3 = 0
y = -3
Hence, the equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3.
Learn more about slope intercept form here
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Answer:
Step-by-step explanation:
Angle 2= 50
angle 1= 180-50= 130 degrees (linear pair (sum 180))
angle 3= 130 degrees (vertically oposite angles are equal)
angle 6= 130 degrees (alternate interior angles)
angle 5= 180-130= 50 degrees (linear pair)
i hope this helps :)
Answer:
y = -3x + 4
Step-by-step explanation:
I graphed the equation and the point given on the graph below. The other line is the equation that is parallel.
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Answer:
y = - 2
Step-by-step explanation:

Answer:
A≈534.07
Step-by-step explanation:
A=2πrh+2πr^2