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Mnenie [13.5K]
2 years ago
14

Got a Home wrestling meet so wish me luck guys and gals

Mathematics
1 answer:
allsm [11]2 years ago
3 0

Answer:

ill wish u luck getting ur a. $. $ down to pick my short body up

Step-by-step explanation:

You might be interested in
Factor −1/4 out of −1/2x−5/4y..ㅤ
hammer [34]

Answer:

  • - 1/4 (2x + 5y)

Step-by-step explanation:

Divide each term by - 1/4 first

  • -1/2x ÷ (- 1/4) = 1/2x × 4 = 2x
  • -5/4y ÷ (- 1/4) = 5/4y × 4 = 5y

Now facor out - 1/4

  • - 1/2x - 5/4y =
  • - 1/4 (2x + 5y)
3 0
2 years ago
An oil tanker can be emptied by the main pump in 5 hours. An auxiliary pump can empty the tanker in 7 hours. If the main pump is
r-ruslan [8.4K]

Answer:

so the answer will be 1

Step-by-step explanation:

An oil tanker can be emptied by the main pump in 5 hours.

An auxilary pump can empty the tanker in 14 hours.

If the main pump is started at 7pm, when should the auxilary pump be started

so that the tanker is emptied by 11pm?

:

Let t = no. of hrs to run the Aux pump

:

The main pump will run 4 hr (7 - 11 pm)

:

Let the completed job = 1; (an empty Tanker)

:

The shared work equation

4%2F5 + t%2F14 = 1

Multiply equation by 70 to get rid of the equation, results:

14(4) + 5t = 70

56 + 5t = 70

5t = 70 - 56

5t = 14

t = 14%2F5

t = 2.8 hrs to run the aux pump

:

2.8 hr = 2 + .8(60) = 2 hrs 48 min

:

Subtract 2:48 from 11:00 = 8:12 PM start the aux pump

;

;

Check solution

4/5 + 2.8/14 =

.8 + .2 = 1

6 0
3 years ago
Hi I really need help can anyone help me out
Alex Ar [27]
Number 16 is 13.5 because each half triangle is 1 unif square
8 0
2 years ago
8(-14)/[(-8)-3(-13)]
Nadusha1986 [10]

Hey there!

\bold{\frac{8(-14)}{(-8)-3(-13)}}

  • \bold{8\times-14=-112}
  • \bold{\frac{-112}{(-8)-3(-13)}}
  • \bold{3\times-13=39}
  • \bold{\frac{-112}{-8-39} }
  • \bold{-8-(-39)=31}
  • \boxed{\boxed{\bold{Answer:\frac{-112}{31}}}}

Good luck on your assignment and enjoy your day!

~\bold{LoveYourselfFirst:)}

7 0
3 years ago
Perform the indicated matrix row operation and write the new matrix
Ne4ueva [31]
The given operation involves just swapping the two rows, so carrying out R_1\leftrightarrow R_2 on the matrix gives

\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]
5 0
3 years ago
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