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frozen [14]
1 year ago
6

As an event organizer, you are to host 120guests in a room of dimensions 18m long and 12m wide. You have rectangular tables whic

h are 2m long and 0.75m wide. The number of guests allocated for the top table is 12 and the rest of the guests are on 3springs. NB: cover space is 0.6m i) Sketch the table plan arrangement. ii) Calculate the number of tables required for the top table. iii) Calculate the number of covers on each spring. iv) calculate the number of tables required for each spring. v) What is the purpose of leaving a gangway when arranging tables and chairs for an event?
Mathematics
2 answers:
Free_Kalibri [48]1 year ago
6 0
Answer:
length of the table=2m cover space for a guests=0.6m so cover space for top table is 12=12×0•6=7•3(4×2)=8



Step-by-step explanation:

crimeas [40]1 year ago
3 0

The room, the tables and the guests are illustrations of rectangles and areas.

<h3>How many tables are required for the top table?</h3>

This is calculated using:

Tables = Guest ÷ Guest per top table

So, we have:

Tables = 120 ÷ 12

Evaluate

Tables = 10

Hence, 10 tables are required for the top table

<h3>How many covers are on each spring?</h3>

This is calculated using:

Covers = Number of spring ÷ Cover space

So, we have:

Covers = 3 ÷ 0.6

Evaluate

Covers = 5

Hence, 5 covers are required for each spring

<h3>How many tables are required for each spring?</h3>

This is calculated using:

Tables = Tables for top table ÷ Spring

So, we have:

Tables = 10 ÷ 3

Evaluate

Tables = 3.33

Remove decimal

Tables = 3

Hence, 3 tables are required for each spring

<h3>What is the purpose of leaving a gangway when arranging tables and chairs for an event?</h3>

This is done to allow passage for walkway

Read more about areas at:

brainly.com/question/24487155

#SPJ2

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sattari [20]
We have that

N 1)
a²<span> − 9a + 14 = 0 
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

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(a² − 9a+20.25)=-14+20.25

Rewrite as perfect squares

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a1=4.5+√6.25-----> a1=7

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the solution problem N 1 is the pair {7, 2}


N 2) 

a²<span> + 9a + 14 = 0
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Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3) 

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square  Remember to balance the equation by adding the same constants to each side 

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Rewrite as perfect squares

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a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}


N 4)

a²<span> + 5a − 14 = 0
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Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}


N 5) 

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 5a+6.25)=14+6.25

Rewrite as perfect squares

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2 years ago
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Order of operations (GEMS)
cestrela7 [59]
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Rina8888 [55]

Answer:

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Step-by-step explanation:

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