N+(n+1)+(n+2)+(n+3)+(n+4)+(n+5)=270
We use these terms to represent the first six consecutive integers in the sequence
Now we group like terms:
6n+15=270
Minus 15 from both sides of the equation
6n=255
n=42.5 which is not an integer
Is this a joke question?
Besides that, the 2nd number will be 43.5
Step-by-step explanation:
The outer angle at the top C of the ABC is 112 °. If the bisector of the side AB intersects the side AC at point Q and the segment BQ is perpendicular to AC, find the magnitude of ABC
Answer:
but many of them comes here to do time pass
Answer:
SSS
Step-by-step explanation:
<h2>
Answer: a = ¹/₂ (4 + b)</h2>
<h3>
Step-by-step explanation:</h3>
To solve for 'a' we have to make it the subject of the equation. Since there are two unknowns ('a' & 'b'), we won't get a numerical value of 'a', but an expression in terms of the second unknown 'b'.
Since 2a - b = 4 <em> [add 'b' to both sides]</em>
then 2a = 4 + b <em>[divide both sides by 2 = multiplying by ¹/₂]</em>
a = ¹/₂ (4 + b)